Quantity

For the majority of auctions on eBay, the quantity will be “1,” (single item auction). There is an option available where you can specify the number of items you want to sell in a single auction. This is commonly referred to as a Dutch auction. Dutch Auctions are a bit tricky to understand, and the outcome (sale of your items) is not assured.

Dutch Auctions

If you look at the help file that eBay provides for entry of multiple items in the Quantity entry, you’ll only walk away thinking “if it’s that complex, why bother.” EBay provides the following explanation for Dutch Auctions (Items in BLUE have been added for clarification):

“Online Auction-type listing: List identical multiple items together in an online auction. The winning bid in a multiple item listing is based on the highest bid per item.

Example: Suppose you have 50 hammers, all the same, that you'd like to sell for at least $5.99 each. You would list them as a quantity of 50, and a starting price of $5.99. 

Example: 

For a listing with 10 available items and 2 bidders:

In this case, the lowest successful bid is $5 ($40 Total). So the outcome of this listing is:

Suppose before the auction ends Bidder C decides they want to bid. In order for that bidder to enter a successful bid, their bid must exceed the current high bid value of $6 each. If Bidder C bids $7 for 2 items, the outcome of the auction would be:

Let’s add a couple of final scenarios for Bidder A:

Suppose before the auction ends Bidder A decides they want to win all 8 items. In order for that bidder to enter a successful bid (win 8 items), their bid must exceed the current high bid value of $6 each (Bidder B). If Bidder A bids $8 for 8 items, the outcome of the auction would be:

Suppose before the auction ends Bidder A decides they want to win all 8 items. In order for that bidder to enter a successful bid (win 8 items), their bid must exceed the current high bid value of $6 each (Bidder B). If Bidder A bids $8 for 8 items, the outcome of the auction would be:
  • Bidder A bid $8 each for 8 items, but wins 8 items at $6 each. ($48 Total)
  • Bidder C bid $7 each for 2 items, but wins 2 items at $6 each. ($12 Total)
  • Bidder B bid $6 each for 3 items, but there are no items left so they do not win.

$60 Assured

Suppose before the auction ends Bidder A decides they really only need 6 items. In order for that bidder to enter a successful bid (win 6 items), their bid must exceed their previous total bid value ($40) & a current successful bidder’s bid. In this case Bidder A must bid above $40 total. For 6 items that comes to a bid of around $6.75 each ($6.67). If Bidder A bids $6.75 for 6 items, the outcome of the auction would be:
  • Bidder C bid $7 each for 2 items, but wins 2 items at $6 each. ($12 Total)
  • Bidder A bid $6.75 each for 6 items, but wins 6 items at $6 each. ($36 Total)
  • Bidder B bid $6 each for 3 items, but wins 2 items at $6 each. ($12 Total – Note: This bidder wanted 3 so they may not complete their purchase)

$48 Assured, $12 Potential

As you can easily see Dutch Auctions are a little complex to get your arms around. I spent the better part of the day figuring this out the first time myself, but they do provide you with a viable method of liquidating multiple items of the same type.